Optimal. Leaf size=637 \[ \frac{\left (b^2-4 a c\right )^{3/4} \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )^2}} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right ),\frac{1}{2}\right )}{40 \sqrt{2} c^{15/4} (b+2 c x)}+\frac{e \left (a+b x+c x^2\right )^{3/4} \left (-2 c e (40 a e+147 b d)+77 b^2 e^2+66 c e x (2 c d-b e)+360 c^2 d^2\right )}{210 c^3}+\frac{(b+2 c x) \sqrt [4]{a+b x+c x^2} (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right )}{20 c^{7/2} \sqrt{b^2-4 a c} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )}-\frac{\left (b^2-4 a c\right )^{3/4} \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )^2}} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac{1}{2}\right )}{20 \sqrt{2} c^{15/4} (b+2 c x)}+\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c} \]
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Rubi [A] time = 0.727933, antiderivative size = 637, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {742, 779, 623, 305, 220, 1196} \[ \frac{e \left (a+b x+c x^2\right )^{3/4} \left (-2 c e (40 a e+147 b d)+77 b^2 e^2+66 c e x (2 c d-b e)+360 c^2 d^2\right )}{210 c^3}+\frac{(b+2 c x) \sqrt [4]{a+b x+c x^2} (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right )}{20 c^{7/2} \sqrt{b^2-4 a c} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )}+\frac{\left (b^2-4 a c\right )^{3/4} \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )^2}} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac{1}{2}\right )}{40 \sqrt{2} c^{15/4} (b+2 c x)}-\frac{\left (b^2-4 a c\right )^{3/4} \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right )^2}} \left (\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac{1}{2}\right )}{20 \sqrt{2} c^{15/4} (b+2 c x)}+\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c} \]
Antiderivative was successfully verified.
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Rule 742
Rule 779
Rule 623
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{(d+e x)^3}{\sqrt [4]{a+b x+c x^2}} \, dx &=\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c}+\frac{2 \int \frac{(d+e x) \left (\frac{1}{4} \left (14 c d^2-3 b d e-8 a e^2\right )+\frac{11}{4} e (2 c d-b e) x\right )}{\sqrt [4]{a+b x+c x^2}} \, dx}{7 c}\\ &=\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c}+\frac{e \left (360 c^2 d^2+77 b^2 e^2-2 c e (147 b d+40 a e)+66 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{3/4}}{210 c^3}+\frac{\left ((2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right )\right ) \int \frac{1}{\sqrt [4]{a+b x+c x^2}} \, dx}{40 c^3}\\ &=\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c}+\frac{e \left (360 c^2 d^2+77 b^2 e^2-2 c e (147 b d+40 a e)+66 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{3/4}}{210 c^3}+\frac{\left ((2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) \sqrt{(b+2 c x)^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{10 c^3 (b+2 c x)}\\ &=\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c}+\frac{e \left (360 c^2 d^2+77 b^2 e^2-2 c e (147 b d+40 a e)+66 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{3/4}}{210 c^3}+\frac{\left (\sqrt{b^2-4 a c} (2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) \sqrt{(b+2 c x)^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{20 c^{7/2} (b+2 c x)}-\frac{\left (\sqrt{b^2-4 a c} (2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) \sqrt{(b+2 c x)^2}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{2 \sqrt{c} x^2}{\sqrt{b^2-4 a c}}}{\sqrt{b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{20 c^{7/2} (b+2 c x)}\\ &=\frac{2 e (d+e x)^2 \left (a+b x+c x^2\right )^{3/4}}{7 c}+\frac{e \left (360 c^2 d^2+77 b^2 e^2-2 c e (147 b d+40 a e)+66 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{3/4}}{210 c^3}+\frac{(2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{20 c^{7/2} \sqrt{b^2-4 a c} \left (1+\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}\right )}-\frac{\left (b^2-4 a c\right )^{3/4} (2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}\right )^2}} \left (1+\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac{1}{2}\right )}{20 \sqrt{2} c^{15/4} (b+2 c x)}+\frac{\left (b^2-4 a c\right )^{3/4} (2 c d-b e) \left (20 c^2 d^2+11 b^2 e^2-4 c e (5 b d+6 a e)\right ) \sqrt{\frac{(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}\right )^2}} \left (1+\frac{2 \sqrt{c} \sqrt{a+b x+c x^2}}{\sqrt{b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac{1}{2}\right )}{40 \sqrt{2} c^{15/4} (b+2 c x)}\\ \end{align*}
Mathematica [C] time = 0.306702, size = 211, normalized size = 0.33 \[ \frac{\frac{21 (b+2 c x) \sqrt [4]{\frac{c (a+x (b+c x))}{4 a c-b^2}} (2 c d-b e) \left (-4 c e (6 a e+5 b d)+11 b^2 e^2+20 c^2 d^2\right ) \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{3}{2};\frac{(b+2 c x)^2}{b^2-4 a c}\right )}{8 \sqrt{2} c^3}+\frac{e (a+x (b+c x)) \left (-2 c e (40 a e+147 b d+33 b e x)+77 b^2 e^2+12 c^2 d (30 d+11 e x)\right )}{2 c^2}+30 e (d+e x)^2 (a+x (b+c x))}{105 c \sqrt [4]{a+x (b+c x)}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.994, size = 0, normalized size = 0. \begin{align*} \int{ \left ( ex+d \right ) ^{3}{\frac{1}{\sqrt [4]{c{x}^{2}+bx+a}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac{1}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{e^{3} x^{3} + 3 \, d e^{2} x^{2} + 3 \, d^{2} e x + d^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac{1}{4}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d + e x\right )^{3}}{\sqrt [4]{a + b x + c x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{3}}{{\left (c x^{2} + b x + a\right )}^{\frac{1}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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